Example:
Assume that the wave function associated with an
electron constrained to one dimension is given by
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where a is a constant associated with the width of the wave function and k0 is related to the momentum of the electron. What is the probability of finding the electron at x = +2a?
The operator associated with a position measurement
is given by
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(1.1)
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where d(x-x0)
is known as the Dirac delta function. It has the property that
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The probability of finding the electron at x = +2a is
then given by

Every physically measurable quantity has a corresponding
operator. This is not as complicated as it may seem, since most measurable
quantities can be written as a function of a few basic quantities. For
example, the operator for momentum (in one dimension) is given by
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(1.2)
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Using this, the operator for total energy in one dimension (assuming
that the potential can be written as a function of position only) becomes
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(1.3)
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For every operator, there is a special set of wave
functions. These functions are those which satisfy the relationship
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(1.4)
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in other words, the effect of the operator on the wave function is that
it returns a multiple of the same wave function. These wave functions are
called the eigenfunctions of the operator, and the multipliers are known
as the eigenvalues. For the energy operator, (1.4) becomes
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(1.5)
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This is know as the Schrodinger equation.
Example:
What are the energy eigenfunctions and eigenvalues
associated with free space (V = 0)?
The Schrodinger equation for free space is
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Since E is a constant, the solutions can be seen to be
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where C1 and C2 are constants determined by normalization, and E can take on any value.
Example:
What are the energy eigenfunctions and eigenvalues
associates with a potential well is defined by
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We can break the problem into two parts, depending
on the value of V. For 0 < x < 2a, the potential
is zero. Thus, the solutions are given by the eigenfunctions in the previous
example. Since the potential is infinite everywhere else, the only non-infinite
solution is a zero function. For completeness, we require the eigenfunctions
to be continuous. Thus, we require that the interior eigenfunction go to
zero at x = 0 and at x = 2a. This leads to a solution
of the form
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where n = 1, 2, 3, …. Substituting this back into the Schrodinger
equation, we find that the allowed energy values are
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In addition to classical quantities, quantum mechanics
introduces some new quantities. One of the more important ones (from a
thermal physics standpoint) is that of spin. Spin can be thought of as
a type of angular momentum; one which is integral to the particle. All
of the fundamental particles in the universe (electrons, protons, neutrons,
etc.) have a spin equal to ½. Particles associated with the carriers
of force (photons, gluons, etc.) have a spin equal to 1. Note that here
we are referring to the magnitude of the spin. The "z" component can take
on integral values whose magnitude can not exceed the total spin magnitude.
Thus, a spin ½ object can have components of +1/2 and –1/2. Composite
objects, such as nuclei, atoms and molecules, have a spin which has maximal
values equal to the total number of particles divided by 2. The wave function
associated with these objects is found by multiplying together the wave
functions of the individual particles then summing together all of the
possible permutations of these particles.
One of the more interesting discoveries of quantum
physics was that particles with half integer spin obey slightly different
laws of physics than those with full integer spin. This can be described
by realizing that the symmetry or antisymmetry of the composite wave function
under the interchange of two particles is a characteristic of the object.
In particular, objects consisting of identical particles of half-odd-integral
spin (i.e. spin 1/2, 3/2, …) are described by antisymmetric wave functions.
Such objects are called fermions, and are said to obey Fermi-Dirac statistics.
Objects consisting of identical particles of integral spin (spin 0, 1,
2, …) are described by symmetric wave functions. Such particles are called
bosons, and are said to obey Bose-Einstein statistics.
The requirement that systems consisting of half-odd-integral
spin have an antisymmetric wave function has a unique side effect. Consider
two electrons which are in the same spin state and have the same energy.
Then the wave function which represents the system must be written as
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(1.6)
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Notice that if the two electrons are put in the same location, so that they become indistinguishable, the wave function vanishes. Thus a state of given energy, angular moment, parity, and so on, can be occupied by two electrons only if they have opposite spin, and then only by two electrons. This is known as the Pauli exclusion principle. This difference between fermions and bosons will become important later during our studies of thermal physics.
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(1.7)
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where N is the total number of trials and ni
is the number of times Xi occurs. How do we combine probabilities?
The probability that a result of Xi or Xj
occurs is
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(1.8)
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Similarly, the probability that two independent measurements,
X
and Y, would produce results Xi and Yj
is
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(1.9)
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so we see that probabilities are additive, and if the measurements are independent, commutative.
Example:
What is the probability of throwing a 7 on 2 dice?
On a single die, the probability of throwing any specific point is 1/6. Thus, the probability of rolling any specific combination on two dice is (1/6)(1/6) = 1/36. How many different combinations add up to 7? Considering each die independently, we have
1+6, 2+5, 3+4, 4+3, 5+2, 6+1
so there are 6 possible combinations, each with probability 1/36. Thus the total probability is 6/36, or 1/6.
Example:
What is the probability of rolling a 3?
The possible combinations are just 1+2 and 2+1, so the probability is 2/36, or 1/18.
Example:
When drawing two cards, what is the probability
of drawing a 3 of hearts and a 5 of diamonds?
The probability of drawing a 3 of hearts on the first draw is 1/52. But now there are only 51 cards left, so the probability of drawing a 5 of diamonds on the second draw is 1/51. Thus, since the two draws are independent of each other, the total probability is
(1/52)(1/51) = 1/2652
If we ask what the probability is regardless of order, we see that the probability is just doubled to 1/1326.
Example:
What is the probability of drawing three hearts
in a row?
P(3 hearts) = (13/52)(12/51)(11/50) = 1716/132600
So far we have talked about discrete probabilities,
in
other words the result could take only a discrete number of answers. What
if the result was continuous? To handle continuous probabilities, we define
a probability density, p(x), such that
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We can use the probability density to calculate the weighed average
value, or expectation value, of x:
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(1.10)
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Similarly, for a function f(x),
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(1.11)
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