P(e1) = g(U0-e1)
Notice that this is different from the relationship we encountered before between the probability and the multiplicity factor. Before, we were asking what is the probability of finding the state in a specific quantum state, given an energy es. There the probability was
P(specific state) = 1/g(es)
Now, we are asking what the probability of finding the system in any quantum state with the energy es (and satisfying any other conditions that we place on it), out of all of the states available to it. Here the probability is
P(es) = g(es)
Returning to the system in contact with the reservoir,
we can ask what is the ratio of the probability that the system is in one
of the quantum states with energy el
to the probability that the system is in one of the quantum states with
energy e2. Then we get
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(5.1)
|
We can restate this in terms of the entropy. Recalling the definition
of entropy, we see that the ratio becomes
![]()
or
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(5.2)
|
where Ds = s(U0-e1)
- s(U0-e2).
If we expand s(U0-e1)
and s(U0-e2)
as Taylor series around the entropy of the reservoir, s(U0),
we get
![]()
but
,
so this becomes
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(5.3)
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If we let the reservoir become infinitely large, all of the higher order
terms vanish. Substituting this into Ds, we
see that
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(5.4)
|
Thus, the probability becomes
![]() |
(5.5)
|
A term of the form exp(-e/t)
is called a Boltzmann factor.
Using Boltzmann factors, we can build another function
which is of great use to thermal physics. This is the partition function,
and
it is defined to be
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(5.6)
|
It is the sum over the Boltzmann factors associated with all of the
allowed states. Notice that the partition function acts as the normalization
constant for the Boltzmann factor to be used as a measurement of probability
|
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(5.7)
|
This result is one of the most useful ones in statistical physics. As a result of this, we can determine the most likely result of any experimental measurement in thermal physics.
Example:
Given a system in contact with a reservoir, what
is the average energy of the system?
![]() |
(5.8)
|
As a specific example, consider a single particle with two energy states.

so

as
.
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|
(5.9)
|
Since s is dimensionless in fundamental units,
we see that CV is also dimensionless in these units.
The specific heat is defined as the heat capacity per unit mass. For the
system discussed above, the heat capacity is

If we graph both <e>/e
and CV as functions of t/e,
we get

The bump in the plot of CV verses t/e is called the Schottky anomaly.
![]()
Let the pressure associated with the change in volume be applied normal
to all of the faces of the cube. Then the mechanical work done in changing
the volume from V to V-DV
is equal to
![]()
Recall that the work is defined to be the scalar product of the force applied with the distance traveled, and that classically we define the pressure to be the force per unit area. Let A be the area of one face of the cube. Then the change in volume can be written as
DV = A(Dx + Dy + Dz)
This allows us to finally write

Thus, ps, which is the pressure of state es,
is
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(5.10)
|
Defining the general pressure to be the average over all of the states
of the ensemble and letting the change in volume go to zero, yields
|
|
(5.11)
|
where U is the energy of the system, <e>.
Notice that we kept the entropy constant in the derivative. This is because
the process was defined such that the number of states for the system remained
unchanged. Another useful expression for the pressure can be derived from
the fact that the entropy is held constant. Recall that the entropy is
usually a function of both the number of particles and the energy. The
number of particles can be related to the volume of the system since each
particle can be assumed to occupy some average volume of space. Thus, s
= s(U,V). For an infinitesimal
change in s
![]()
For an isotropic process this change is zero, so
![]()
or
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(5.12)
|
Where we have used the definitions
and
.
Substituting this result back into ds yields
the useful thermodynamic identity,
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(5.13)
|
This is a generalized conservation of energy equation, where t ds is the heat put into the system and p dV is the work done by the system.